The differential equation d^2y/dx^2 x(dy/dx) siny x^2 = 0 is of the following type`x^y*y^x=1` Find `dy/dx` `x^y*y^x=1` Find `dy/dx` Books Physics NCERT DC Pandey Sunil Batra HC Verma Pradeep Errorless Chemistry If , find and prove that 257 139k LIKES 2786k VIEWS 2786k SHARES FindRead it This problem has been solved!

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X^y.y^x=m find dy/dx
X^y.y^x=m find dy/dx- 1answer If y = sec^1((x 1)/(x 1)) sin^1((x 1)/(x 1)), then write the value of dy/dx askedApr in Differentiationby Kaina(304kpoints) differentiation class12 Welcome to Sarthaks eConnect A unique platform where students can interact with teachers/experts/students to get solutions to their queriesSo we get (1/y)(dy/dx) = log(2) 4) We want to find dy/dx, which is on the LHS To get this dy/dx on its own we can multiply both sides by y So we get dy/dx = y log(2) 5) To finish this question we need to sub in for y and then we have an answer for dy/dx




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If x^y=y^x ,then find dy/dx Updated On 57 To keep watching this video solution for FREE, Download our App Join the 2 Crores Student community now!Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreTake log on both sides == y log x = log u == y*1/x logx * dy/dx (by products rule) = 1/u du / dx ==du/dx = x y (y/x logx dy/dx) let y x = v ;
How to find dy/dx by implicit differentiation given that e^ (x^2y) = x y Here's the 4 simple steps we will take in order to find dy/dx from the given equation e^ (x^2y) = x y 021Take log on both sides == x log y = logv == x*1/ydy/dx logy*1 (by products rule) = 1/v dv/dx == dv/dx = y x (x/y dy/dx logy) == u v = a b differentiating wrt x we get , du/dx dv/dx = 0 ==`x^y=y^x` then find `(dy)/(dx)` `x^y=y^x` then find `(dy)/(dx)` Doubtnut is better on App Paiye sabhi sawalon ka Video solution sirf photo khinch kar Open App Continue with Mobile Browser Books Physics NCERT DC Pandey Sunil Batra HC Verma Pradeep Errorless Chemistry
If y = sin^1 (x√(1 x) √x √(1 x^2) and dy/dx = 1/2 √x√(1x^2) p, then p is equal toIf sin 2 x 2 cos y xy = 0, then dy/dx = If Slope Of Tangent To Curve Y X 3 At A Point Is Equal To Ordinate Of A Point Then Point Is Leave a Comment Cancel replyFind dy/dx by implicit differentiation xe^y = x y Boost your resume with certification as an expert in up to 15 unique STEM subjects this summer




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Equalling the red y curve and the blue x curve happens also only in (1,1) and shows that dy/dx = dx/dy = 1 Now for z=z (x,y) Equalling the blue and green functions happens in the red curve x=t, y=t, z=t^t ! Ex 55, 12 Find 𝑑𝑦/𝑑𝑥 of the functions in, 𝑥^𝑦 𝑦^𝑥 = 1 𝑥^𝑦 𝑦^𝑥 = 1 Let 𝑢 = 𝑥^𝑦 , 𝑣 = 𝑦^𝑥 Hence, 𝑢𝑣=1 Differentiating both sides 𝑤𝑟𝑡𝑥 (𝑑(𝑣〖 𝑢〗))/𝑑𝑥 = 𝑑(1)/𝑑𝑥 𝑑𝑣/𝑑𝑥 𝑑𝑢/𝑑𝑥 = 0 (Derivative of answered by Nakul01 (369k points) selected by KumariMuskan Best answer Given, xy = yx Taking logarithm on both sides, we get y log x = x log y Differentiating both sides, wrt x y (1/x) log x (dy/dx) = x (1/y) (dy/dx) log y 1 (y/x) (log x) (dy/dx) = (x/y) (dy/dx) log y



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find dy/dx x^yy^x=e^xyFind dy/dx y=3^x y = 3x y = 3 x Differentiate both sides of the equation d dx (y) = d dx (3x) d d x ( y) = d d x ( 3 x) The derivative of y y with respect to x x is y' y ′ y' y ′ Differentiate using the Exponential Rule which states that d dx ax d d x a x is axln(a) a xYx = xyTaking log on both sides⇒ logyx = logxy⇒ xlogy = ylogx⇒ xy1 dxdy logy×1= xy logxdxdy ⇒ (yx −logx) dxdy = xy −logy⇒ dxdy = yx −logxxy −logy = x(x−ylogx)y(y−xlogy) = x(ylogx−x)y(xlogy−y)




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Till infinite Find dy/dx Please give the solutionWrite in the form y=x^y since x^x^x^x is till infinite, we can consider it to be y, then take l Book a Trial With Our Experts ×See the answer See the answer See the answer done loading Show transcribed image text Expert Answer Who are the experts? To ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW If `x^y=y^x`,then find` dy/dx`




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Get an answer for 'If x y = xy, then dy/dx = Please explain step by step' and find homework help for other Math questions at eNotesFind dy/dx xe^y=xy xey = x − y x e y = x y Differentiate both sides of the equation d dx (xey) = d dx (x−y) d d x ( x e y) = d d x ( x y) Differentiate the If x^y y^x = a^b, find dy/dx Sarthaks eConnect Largest Online Education Community




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Question Find dy/dx by implicit differentiation x sin(y) y sin(x) = 2 x cos(y) sin(x) y' x sin(y) y cos(x) Need Help?Find dy/dx given x^3 3 x^2 y 2 x y^2 = 12 WolframAlpha Have a question about using WolframAlpha? Question Solve dy/dx y/x =xe^x This problem has been solved!




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Find dy/dx y=e^x y = ex y = e x Differentiate both sides of the equation d dx (y) = d dx (ex) d d x ( y) = d d x ( e x) The derivative of y y with respect to x x is y' y ′ y' y ′ Differentiate using the Exponential Rule which states that d dx ax d d x a x is axln(a) a x ln ( a) where a a = e e ex e x Davneet Singh is a graduate from Indian Institute of Technology, Kanpur He has been teaching from the past 10 years He provides courses for Maths and Science at TeachooThe functions apart and



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x y y x = a b, here ab is const let x y = u ;Click here👆to get an answer to your question ️ If y = x^x , then find dydx Join / Login > 12th > Maths > Continuity and Differentiability > Logarithmic DifferentiationWatch Video in App This browser does not support the video element 5453 k 1714 k Answer



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Find dy/dx of y = a^x To differentiate a function of the form y=a^x you need to use a neat little trick to rewrite a^x in the form of something you already know how to differentiate Using the fact that e^ln(x) is equal to x, y = a^x can be written as e^(ln(a)^x) Using log rules ln(a)^x can be written as xlna so now y can now be expressed as yFind `dy/dx` of function x y y x = 1 Advertisement Remove all ads Explanation dy dx = x y ydy = xdx by exploiting the notation (separation) ∫ydy = ∫xdx further exploiting the notation 1 2 y2 = 1 2x2 d y2 = x2 2d x2 −y2 = − 2d x2 −y2 = c where c = −2d Depending on whether c is positive, negative or zero you get a hyperbola open to the x axis, open to the y =axis, or a pair of straight lines through the




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If y = (log x)x xlog x, find "dy"/"dx" Mathematics Advertisement Remove all ads Advertisement Remove all ads Advertisement Remove all ads Sum If y = (log x) x x log x, find `"dy"/"dx"` Advertisement Remove all ads Solution Show Solution Let y =(log x) x x log x Also, let u =(log x) x and v = x log xExperts are tested by Chegg as specialists in their subject area We review their content and use your feedback to keep the quality high Ex 56, 6 If x and y are connected parametrically by the equations without eliminating the parameter, Find 𝑑𝑦/𝑑𝑥, 𝑥 = 𝑎 (𝜃 – sin𝜃), 𝑦 = 𝑎 (1 cos𝜃)Here 𝑑𝑦/𝑑𝑥 = (𝑑𝑦/𝑑𝜃)/ (𝑑𝑥/𝑑𝜃) Calculating 𝒅𝒚/𝒅𝜽 𝑦 = 𝑎 (1cos𝜃) 𝑑𝑦/𝑑𝜃 = 𝑑 (𝑎 (1




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Doing the same, we get that #y^x(lny x/y(dy/dx))# Thus the derivative of the entire function is given by #x^ylnx(dy/dx) x^y(y/x) y^xln y y^x x/y(dy/dx) = 0#Calculus (8th Edition) Edit edition Solutions for Chapter 35 Problem 10E Find dy/dx by implicit differentiationxey = x – y Solutions for problems in chapter 35 1E Ex 56, 4 If x and y are connected parametrically by the equations without eliminating the parameter, Find 𝑑𝑦/𝑑𝑥, 𝑥 = 4𝑡, 𝑦 = 4/𝑡Here 𝑑𝑦/𝑑𝑥 = (𝑑𝑦/𝑑𝑡)/ (𝑑𝑥/𝑑𝑡) Calculating 𝒅𝒚/𝒅𝒕 𝑑𝑦/𝑑𝑡 " " = 𝑑/𝑑𝑡 (4/𝑡) 𝑑𝑦/𝑑𝑡 = 4 𝑑/𝑑𝑡 (1/𝑡) 𝑑𝑦/𝑑𝑡 = − 𝟒/𝒕^𝟐 Calculating 𝒅𝒙/𝒅𝒕 𝑑𝑥/𝑑𝑡 = 𝑑 (4𝑡)/𝑑𝑡 𝑑𝑥/𝑑𝑡 " " =




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Example 25 Find 𝑑𝑦/𝑑𝑥 , if y sin y = cos𝑥 y sin y = cos x Differentiating both sides by x 𝑑𝑦/𝑑𝑥 (𝑑(sin〖𝑦)〗)/𝑑𝑥 = (𝒅(𝐜𝐨𝐬〖𝒙)〗)/𝒅𝒙 𝑑𝑦/𝑑𝑥 (𝑑(〖sin 〗〖𝑦)〗)/𝑑𝑥 = − sin x 𝑑𝑦/𝑑𝑥 (𝒅(𝐬𝐢𝐧〖𝒚)〗)/𝒅𝒚 𝑑𝑦/𝑑𝑥 = − sin x 𝑑𝑦/𝑑𝑥See the answer See the answer See the answer done loading Show transcribed image text Expert Answer Who are the experts?Calculus Find dy/dx y=xe^x y = xex y = x e x Differentiate both sides of the equation d dx (y) = d dx (xex) d d x ( y) = d d x ( x e x) The derivative of y y with respect to x x is y' y ′ y' y ′ Differentiate the right side of the equation Tap for more steps



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Mulitply both sides by $dx$ $$d(x^y)=yx^{y1}dxx^y\ln(x)dy, \qquad d(y^x)=y^x\ln(y)dx xy^{x1}dy$$ As you can see, the derivative is of $x^y$ and $y^x$ is the derivative with respect to $x$ on the left side $$ the derivative with repsect to $y$ on the right side




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